5x+4x=9x^2

Solution for 5x+4x=9x^2 equation:

5x+4x=9x^2

We move all terms to the left:

5x+4x-(9x^2)=0

determiningTheFunctionDomain
-9x^2+5x+4x=0

We add all the numbers together, and all the variables

-9x^2+9x=0

a = -9; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·(-9)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*-9}=\frac{-18}{-18}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*-9}=\frac{0}{-18}
=0
$